Karate5650
17.01.2020 •
Mathematics
Arectangular painting has dimensions x + 8. the painting has a frame that is 3 inches wide. the total area of the picture and the frame is 384 inches ^2. find the dimensions of the painting in inches.
1) none of the choices are correct.
2) x² + 20x + 84 = 384
3) x² + 13x + 33 = 384
4) x² + 13x - 351 = 0
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Ответ:
The dimensions of the painting are 10 in by 18 in
Step-by-step explanation:
The complete question is
A rectangular painting has dimensions x and x + 8. The painting has a frame that is 3 inches wide. The total area of the picture and the frame is 384 inches ^2. Find the dimensions of the painting in inches
we know that
The area of the painting is
The total area of the picture and the frame is 384 inches ^2
so
solve the quadratic equation by graphing
using a graphing tool
The solution is x=10 in
see the attached figure
therefore
The dimensions of the painting are 10 in by 18 in
Ответ:
40÷85 =÷ 0.47058823529