Arectangular piece of poster board measurea 60 centimeters by 80 centimeters. linn draws the net of a box on the poster board and cuts it out. if the box measures 10 centimeters by 16 centimeters by 27 centimeters, what is the area of the poster board plz you

To find the answer for that question you have to find the area of rectangle first, so you say 60*80 which equals to 4800 cm squared and then find the area of the box and not its volume so you say: 2(16*10)=2*160=320 cm squared
                                                              4(16*27)=4*432=1728 cm squared 
add 320+1728= 2048 cm squared 
Finally, to find the area of the left poster board you have to subtract the area of the rectangle which is 4800 cm squared by the area of the box which is 2048 cm squared so 4800-2048=2752 cm squared 

2(8a + 9).

Step-by-step explanation:

The Greatest Common Factor is so we have:

2(8a + 9).