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williamnason123
15.07.2019 •
Mathematics
Arectangular porch has an area of 75 square feet.the length of the porch is 4 feet longer than the width.what is the width of the porch ?
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Ответ:
x^2 + 4x -75 = 0
x = [-4 +sq root (316)] / 2
x = 13.7763888346 / 2
x = 6.8881944173
x = 6.888 (rounded)
Width = 6.888
Length = Width +4
Width = 10.888
Double Check
6.888 * 10.888 = 75 square feet
Ответ:
Slope of the first is chg y/chg x or 4/2=2
now use point slope formula y-y1=m(x-x1), where m is the slope and (x1,y1) is the point.
y-3=2(x-0)
y=2x+3
The other
slope is 2/-2=-1
y-5=-1(x-1)
y-5=-x+1
y=-x+6
Slopes aren't the same or a negative reciprocal, so they intersect. Coincident.
substitute the second into the first
-x+6=2x+3
3x=3
x=1
Therefore, y=2(1)+3=5. The point is (1,5) where they intersect.
Check with the second
5=-1+6, check