Aregular pyramid has a height of 12 cm in a square

Ответ:

luisafer127

11.01.2022

$\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad 
\begin{cases}
B=\textit{area of the base}\\
h=height\\
----------\\
h=12\\
V=236
\end{cases}\implies 236=\cfrac{1}{3}B(12)
\\\\\\
3\cdot 236=12B\implies \cfrac{708}{12}=B\implies 59=B$

now, is a square pyramid, like the picture below, so the base is just a square, so B = length * width, thus

$\bf B=length\cdot width\quad 
\begin{cases}
length=x\\
width=x\\
B=59
\end{cases}\implies B=x\cdot x\implies B=x^2
\\\\\\
59=x^2\implies \sqrt{59}=x$

Aregular pyramid has a height of 12 cm in a square base if the volume of the pier mid is 236 cm³ how