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angelnjones42
01.09.2019 •
Mathematics
Aresearcher finds that, of 982 men who died in 2002, 221 died from some heart disease. also, of the 982 men, 334 had at least one parent who had some heart disease. of the latter 334 men, 111 died from some heart disease. a man is selected from the group of 982. given that neither of his parents had some heart disease, find the conditional probability that this man died of some heart disease.
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Ответ:
Events:
H=died of heart disease
~H=did not die of heart disease
P=at least one parent has heart disease
~P=no parent have heart disease
From given information, we can construct contingency diagram as follows:
H ~H Total
P 111 334
~P
Total 221 982
From the above diagram, we calculate
|~P & H| = 221-111=110
| P & ~H | = 334-111 = 223
Total | ~P | = 982-334=648
Total | ~H | = 982-221=761
| ~H & ~P | = 648-110 = 538
=>
H ~H Total
P 111 223 334
~P 110 538 648
Total 221 761 982
=>
P(H|~P)=110/648=55/324
=0.170 (approx.)
Ответ:
The answer is 500
Step-by-step explanation: