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evarod
27.07.2019 •
Mathematics
Aripe pear falls from a tree and lands on the ground. as it hit the ground, the pear had a speed of 34 feet per second. approximately how far up in the tree was the pear before it fell? use the formula below, and assume that the acceleration due to gravity is 32 feet per second squared: s=pi2gh
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Ответ:
Therefore, for conservation of energy we have:
mgh = (1/2) m * v ^ 2
From here we clear the speed:
v = root (2 * g * h)
The height will then be:
h = v ^ 2 / (2 * g)
Substituting the values:
h = (34) ^ 2 / (2 * (32))
h = 18.0625 feet
The pear before it fell was 18.0625 feet up in the tree.
Ответ:
18.0625 feet
Step-by-step explanation:
Given : The pear had a speed of 34 feet per second.
To Find: Approximately how far up in the tree was the pear before it fell?
Solution:
We are given that assume that the acceleration due to gravity is 32 feet per second squared
Formula =![s=\sqrt{2gh}](/tpl/images/0140/4858/71147.png)
Where s is the speed , g is the acceleration due to gravity and h is the height
So,![34=\sqrt{2(32)h}](/tpl/images/0140/4858/aa8e2.png)
Hence the pear was at height of 18.0625 feet before it fell.
Ответ:
Multiply that by 100
The answer is 70%