Mathematics: Aryana wants to invest $43,000. She has two options. Option A gives her 6% compounded quarterly. Option B gives her 6% simple interest annually. Which option earns higher interest after 3 years and by how much?

OR CStep-by-step explanation:Start off by: Then You then get my answer! Hope this helps!!...

Aryana wants to invest $43,000. She has two options.

kameronmouton

28.01.2022

Option A earns higher interest($84115.58)

the difference in interest between the two option is $197.9

Step-by-step explanation:

In the problem we are going to apply both the simple interest formula and compound interest formula and compare which has the best/higher returns

Given data

Principal P= $43,000

Rate r= 6%= 0.06

time t= 3years

n= 4 (applicable for compound interest compounded quarterly)

solving for option A gives her 6% compounded quarterly

the compound interest formula is

$A= P(1+\frac{r}{n} )^n^t\\A= 43000(1+\frac{0.06}{4} )^{4} ^*^3$

$A=43000(1+0.015)^{12} \\A=43000(1.015)^{12} \\A=43000*1.1956\\A= 51411.58$

Interest is A-P= 51411.58-43000= 8411.58 =$8411.58

solving for option B which gives her 6% simple interest annually

the simple interest formula is

$A=P(1+r)^{t} \\A=43000(1+0.06)^3\\A=43000(1.06)^3\\A=43000*1.191\\A= 51213.68$

Interest is A-P=51213.68-43000= 8213.68 = $8213.68

calculating the diference in interest between the two options we have

8411.58-8213.68= 197.9 = $197.9

Option A earns higher interest

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beverly9662

23.09.2022

5x+2 OR C

Step-by-step explanation:

Start off by: $\frac{5x^2+12x+4}{x+2}$

Then $\mathrm{Factor}\:5x^2+12x+4:\quad \left(x+2\right)\left(5x+2\right)$ $=\frac{\left(x+2\right)\left(5x+2\right)}{x+2}$

$\mathrm{Cancel\:the\:common\:factor:}\:x+2$

You then get my answer! Hope this helps!!

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