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haileesprague1578
22.08.2019 •
Mathematics
As a part of an exercise program, two students, louisa and alfredo, start walking each morning. they live 15 miles away from each other. they decide to meet one day by walking toward one another. after 2 hours they meet. if louisa walks one mile per hour faster than alfredo, find both of their walking speeds.
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Ответ:
s=d/t
t=d/s
so we have several things:
distance of alfredo
speed of alfredo
time of alredo
distance of louisa
speed of louisa
time of louisa
we will represen them as follows
distance of alfredo=d1
speed of alfredo=s1
time of alredo=t1=2=t2
distance of louisa=d2
speed of louisa=s2
time of louisa=t2=2=t1
d=distance
t=time
total d=15 miles
t=2 hours
they both walk towards each other
louisa's speed is 1 mile per hour more than Alfredo so s2=s1+1
so we also have
d1+d2=15
s2=s1+1
t1=t2=2
we want to solve for s1 and s2
d=st
d1=(s1)(2)
d2=(s2)(2)
subsitute s1+1 for s2
d2=(s1+1)(2)
put back ino equation
(s1)(2)+(s1+1)(2)=15
distribute
2s1+2s1+2=15
2(s1)+2(s1)+2=15
add like terms
4(s1)+2=15
subtract 2 from both sides
4(s1)=13
divide both sides by 4
s1=13/4=3 and 1/4 mph
s2=s1+1
s2=3 and 1/4
s2=4 and 1/4 mph
check
d=st
t=2
alfredo's distance=(3 and 1/4) times 2=6 and 1/2
louisa's distance=(4 and 1/4) times 2=8 and 1/2
6 and 1/2+8 and 1/2=6+1/2+8+1/2=14+1=15
Alfredo's walking speed=3 and 1/4 miles per hour
Louisa's walking speed=4 and 1/4 miles per hour
aka
Alredospeed=3.25 mph
Louisaspeed=4.25 mph
Ответ:
5>x
Step-by-step explanation: