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sjdswim
06.07.2019 •
Mathematics
Asalvage ship’s sonar locates wreckage at a 12 degree angle of depression. a diver is lowered 40 meters to the ocean floor. how far does the diver need to walk along the ocean floor to the wreckage? 188.2 units 8.5 m 192.4 m 41.0 m
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Ответ:
The diver need to walk 188.2m along the ocean floor to the wreckage.
Step-by-step explanation:
Check the attachment for diagram.
Using SOH, CAH TOA to get the distance the diver need to walk along the ocean floor to the wreckage,
Note that the angle is a right angled triangle with the height of the triangle being the opposite side and the distance needed as the adjacent side.
Using TOA
Tan(theta) = Opposite/Adjacent
Given theta = 12°
Opposite = 40m
Adjacent side = x
Tan12° = 40/x
x = 40/tan12°
x = 188.2m
Ответ:
First Number-40, Second number-25 Hope this helps!
Step-by-step explanation:
Please give me brainliest, i have never had it before :(