brianaduenas619
03.08.2020 •
Mathematics
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Ответ:
304(pi) g
Step-by-step explanation:
First we find the volume of the hollow ball. Then we find the mass using the volume and density.
Let R = exterior radius = 3 cm
Let r = interior radius = 2 cm
volume = exterior volume - interior volume
volume = (4/3)(pi)R^3 - (4/3)(pi)r^3
volume = (4/3)(pi)(R^3 - r^3)
volume = (4/3)(pi)(3^3 - 2^3) cm^3
volume = (4/3)(pi)(27 - 8) cm^3
volume = (76/3)pi cm^3
Now we use the density and the volume to find the mass.
density = mass/volume
mass = density * volume
mass = 12 g/cm^3 * (76/3)pi cm^3
mass = 304(pi) g
304(pi) g
Ответ:
m=(76π/3 )(12)=304πg
Step-by-step explanation:
volume of sphere=(4πr³)/3
V=4π(2)³/3=32π/3 of the interior
V of exterior=4π(3)³/3=36π
Volume of the whole metal =108π/332π/3=76π/3=25 1/3 π
m=V*D ( volume * density)=
m=(76π/3 )(12)=304πg
Ответ:
answer:
it will be 149.5
step-by-step explanation: