Mathematics: Asensitive measuring device is calibrated so that errors in the measurements it provides are normally distributed with mean 0 and variance 2.00. find the probability that a given error will be between -3 and 3.

Asensitive measuring device is calibrated so that

elizabethhubbe

09.03.2022

0.9660

Step-by-step explanation:

Given: Mean : $\mu =0$

Variance : $\sigma^2=2.00$

⇒ Standard deviation : $\sigma = \sqrt{2}$

The formula to calculate z is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x= -3

$z=\dfrac{-3-0}{\sqrt{2}}=-2.12132034356\approx-2.12$

The P Value = P(z

For x= 3

The P Value = P(z

$\text{Now, }P(-3$

Hence, the probability that a given error will be between -3 and 3=0.9660

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dannyboy938

23.08.2022

Step-by-step explanation:

(x + y)^5 = 1·x^5·y^0 + 5·x^4·y^1 + 10·x^3·y^2 + 10·x^2·y^3 + 5·x^1·y^4 + 1·x^0·y^5

Correct is only A

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