acamjackie25561
28.01.2020 •
Mathematics
Asequence consists of the positive odd integers. what is the sum of the first 12 terms of the sequence?
a. 144
b. 169
c. 115
d. 121
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Ответ:
A
Step-by-step explanation:
The sequence of positive odd numbers is
1, 3, 5, 7, ......
This is an arithmetic sequence with common difference d
d = 3 - 1 = 5 - 3 = 7 - 5 = 2
The sum to n terms of an arithmetic sequence is
= [2a + (n - 1)d ]
where a is the first term
here a = 1, d = 2, n = 12, hence
= [1 + (11 × 2) ]
= 6 [ 2 + (11 × 2) ]
= 6 × 24 = 144 → A
Ответ:
A. 144.
Step-by-step explanation:
We have been given that a sequence consists of the positive odd integers. We are asked to find the sum of the first 12 terms of the sequence.
Our sequence would be: 1, 3, 5, 7, 9, 11, ....,
We will use sum of sequence formula to solve our given problem.
, where,
= 1st term of sequence,
= nth term of sequence,
= Number of terms is the sequence.
Let us find nth term of sequence using formula:
, where,
d = Difference between two consecutive terms of sequence.
Therefore, the sum of 1st 12 terms of the sequence is 144 and option A is the correct choice.
Ответ:
3 + (-5) = -2
-2 + 9 = 7
7 - 6 = 1.
Meaning Jesse's total score is 1.