Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. on the return trip to its resting place, the cheetah travels an average of 70 mph. if the cheetah traveled for 15 minutes, how many minutes did the return trip take to the nearest minute and second? a. set up the table as follows. label the rows “to the river” and “from the river.” label the columns “distance,” “rate,” and “time (in hours).” let t represent the unknown quantity in the problem. fill in the table. b. from the table, set up an equation relating the distances. c. solve the problem. write the answer in a complete sentence, stating it in terms of minutes and seconds.

Part (a): table                          d            r (mph)            t (hrs)to river the          d1                40                  15/60from the river    d2              70                  twhere: d = distance (equal in both trips), r =speed, t = time taken in hours, t = unknown time taken to the river.part (b): equation related to distnacesdistance traveled in both trips is equal. therefore,d1 = d2d1 = 40*(15/60)d2 = 70*tthen,40t*(15/60) = 70*tpart (c): solving the equation in part (b) above to calculate t40*(15/60) = 70t70t = 10t = 10/70 = 1/7 = 1/7*60 = 8.57 minutes = 8 minute + (0.57*60) seconds = 8 minutes and 34 seconds.therefore, return trip took 8 minutes and 34 seconds.

The first and third angles are expressed in terms of the second angle, so it is convenient to first find its value. Let x represent the second angle. Then we have ..
  first ange = x + 24
  second angle = x
  third angle = 4x
And the sum of angles is
  (x + 24) + (x) + (4x) = 180
  6x +24 = 180
  x = (180 -24)/6 = 26

We can now find the measures of the angles as ...
  first angle = 26 + 24 = 50
  second angle = 26
  third angle = 4*26 = 104

The measure of the largest angle is ...
  104 degrees