Assume that there are 5 dimes, 3 nickels, and 2 quarters. in how many possible ways can the selection be made so that the value of the coins is at least 25 cents?

For quarters, 1 way is a quarter.
2 dimes and 1 nickel. Another is again 2 dimes and 1 nickel.

A drama club sold 120 child tickets and 80 adult tickets to a play a child ticket is 3 dollars less than an adult ticket The club sold a total of 640 dollars worth of tickets What were the prices? 



Answer byDon Dfoofnik

CONFIDENCE VOTES 210K

There are three kinds of answers: ones that are mostly right, ones that are mostly wrong, and those that once were right but now are wrong.

The tickets are $5 adult and $2 child.

Here is the algebraic substitution.

A = adult ticket money

C = child ticket money

120C + 80A = 640

C = A-3 (three dollars less)

120 (A-3) + 80A = 640

120 A - 360 + 80A = 640

200 A = 1000