gaboalejandro833
08.11.2019 •
Mathematics
Assume the box contains 9 balls:
4 red, 2 blue, and 3 yellow. a ball is drawn and its color noted. if the ball is yellow, it is replaced; otherwise, it is not. a second ball is then drawn and its color is noted.
what is the probability that the first ball was yellow, given that the second was red?
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Ответ:
P(R2 | Y1) = 4/9 P(Y1) = 1/3
P(R2 | B1) = 1/2 P(B1) = 2/9
P(R2 | R1) = 3/8 P(R1) =4/9
P(R2) = [4/9*1/3] + [1/2*2/9] + 3/8*4/9] = 23/54
P(Y1R2) = P(Y1)*P(R2|Y1) = 1/3*4/9 = 4/27
P(Y1 | R2) = 4/27*54/23 =8/23
hope this help
Ответ:
False
Step-by-step explanation:
If they are translated 3 units right and 4 units up, just add 3 to the x coordinate and 4 to the y coordinate. The results of that don't match.