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stevenabdullatif16
19.11.2019 •
Mathematics
Astore sells two types of toys, a and b. the store owner pays $8 and $14 for each one unit of toy a and b respectively. one unit of toys a yields a profit of $2 while a unit of toys b yields a profit of $3. the store owner estimates that no more than 2000 toys will be sold every month and he does not plan to invest more than $20,000 in inventory of these toys. how many units of each type of toys should be stocked in order to maximize his monthly total profit?
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Ответ:
A = 1333 and B = 667
Step-by-step explanation:
Given that a store sells two types of toys, A and B.
AB
cost 814
Profit23
Objective is to maximize profit
where A = no of toys of A and B = no of toys of B
Constraints are
By solving this equation, we get
(A,B)= (1333,667)
Corner points would be lowest of x and y intercepts in both
(A,B) = (2000,0) and (0,1428)
Profit for![(1333,667) = 2666+2001\\=4667](/tpl/images/0380/6620/69e38.png)
Profit for![(2000,0) =4000](/tpl/images/0380/6620/695fa.png)
Profit for![(0.1428)=4284](/tpl/images/0380/6620/f247c.png)
Since maximum at (1333,667) we find that
to maximize profit A = 1333 and B = 667 to be produced.
Ответ:
12 do both hurdles and long jump
Step-by-step explanation:
3/8 of the team does hurdles, so that number is 3/8·40 = 15.
Of those 15, 4/5 do long jump, so there are ...
4/5·15 = 12 . . . hurdlers who do long jump