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stef76
12.11.2019 •
Mathematics
Astore sold 21 sweatshirts. white ones cost $10.95 and yellow ones cost $12.50. in all, $260.95 worth of sweatshirts were sold. how many of each color were sold?
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Ответ:
The store sold 1 white sweatshirt and 20 yellow sweatshirts
Step-by-step explanation:
Step 1: Express total cost of sweatshirts
Total cost of sweatshirts can be expressed as;
Total cost=(price per white sweatshirt×number of white sweatshirts sold)+(price per yellow sweatshirt×number of yellow sweatshirt sold )
where;
Total cost=$260.95
Price per white sweatshirt=$10.95
number of white sweatshirts sold=w
Price per yellow sweatshirt=$12.50
number of yellow sweatshirt sold=y
Replacing;
260.95=(10.95×w)+(12.5×y)
10.95 w+12.5 y=260.95...equation 1
Step 2: Express total number of sweat shirts sold
Total number of sweatshirts sold=number of white sweatshirts sold+number of yellow sweatshirt sold
where;
Total number of sweatshirts sold=21
number of white sweatshirts sold=w
number of yellow sweatshirt sold=y
replacing;
w+y=21...equation 2
Step 3: Solve simultaneously equation 1 and 2
1(10.95 w+12.5 y=260.95)>>>10.95 w+12.5 y=260.95
-
12.5(w+y=21)>>>12.5 w+12.5 y=262.5
(10.95 w-12.5 w)+(12.5 y-12.5 y)=260.95-262.50
-1.55 w=-1.55
w=1.55/1.55
w=1
Replace the value of w in equation 2
w+y=21
1+y=21
y=21-1=20
The store sold 1 white sweatshirt and 20 yellow sweatshirts
Ответ:
A) both functions are linear
B) f(x) = 7446.4x + 178713.6 and f(x) = 11000x + 179000
C) House 2 will value $106894.4 more than house 1.
Step-by-step explanation:
A) Value Increase from year 1 to year 2:
House 1: 193,606.40 - 186,160 = 7446.4
House 2: 201,000 - 190,000 = 11000
Value Increase from year 2 to year 3:
House 1: 201,350.66 - 193,606.40 = 7744.26
House 2: 212,000 - 201,000 = 11000
This means that a constant increament in x variable gives a constant increament in both houses vales. Then, both functions are linear.
B) The slope is the same as the value increment from one year to the next one.
slope (m) of House 1: 7446.4
slope (m) of House 2: 11000
General formula of a line:
f(x) = mx+b
Replacing with a known point:
House 1
186,160 = 7446.4(1) + b
b = 186,160 - 7446.4 = 178713.6
equation: f(x) = 7446.4x + 178713.6
House 2
190,000 = 11000(1) + b
b = 190,000 - 11000 = 179000
equation: f(x) = 11000x + 179000
C) Replacing x = 30 into each equaiton:
Value of House 1 after 30 years
f(x) = 7446.4(30) + 178713.6 = 402105.6
Value of House 2 after 30 years
f(30) = 11000(30) + 179000 = 509000
Then, house 2 will value 509000 - 402105.6 = $106894.4 more than house 1.