At 9: 00 a.m., a wind speed of 20 miles per hour was recorded. after that, the wind speed was recorded every hour. each measurement showed an increase in wind speed of 3 miles per hour. the strongest wind was recorded at 4: 00 p.m. after that, the wind speeds started to decrease. what was the top wind speed? a.the number of hours it took for the wind speed to reach its minimum for the day b.the miles-per-hour speed of the wind at its maximum point c.the time of day the first measurement was made

Maximum speed = 41 mph

Step-by-step explanation:

Here we see that the speed of wind is increasing by 3 miles per hours. The start time was 9 AM . If we consider it as our starting time i.e h=0 , at 4 PM the value of h will be 7

Hence the speed at various duration will be like this

at

h=0 ; s = 20 Where s is speed of the wind

h=1 ; =23

h=2 ; 26

Let us find the equation from these points , considering h on x asix and s at y axis.

Here for h  =0 , s = 20 , hence y intercept is 20

Also

Let us find the slope

slope m is given as

m=3

The slope intercept form of a line is

y=mx+c

putting values of m and c we get

y=3x+20

Now we have to find the speed of wind at h=7 , hence we put x= 7 and h is n x axis

y=3(7)+20

y=21+20

y=41

Hence maximum speed was 41 mph

Now we have to find the time taken to reach the minimum . For which we are supposed to have rate of decrements , which is not given hence we can not find the exact time after which it attains the minimum speed.

100÷25x20+4÷2-14
Remember to follow the order of operations, Parenthesis Exponents Multiplictation Division Addition Subtraction (PEMDAS)
                                                                
following tat, we would do the division first                    
4x20+4÷2-14
(100/25=4)

80+4÷2-14
(20x4=80)

Now we do 4÷2 (remember, you do multiplication and division first)
80+2-14

now we just add and subtract from left to right:
(80+2=82)
82-14

68 is your final answer