At a charity raffle event they are giving out tickets labeled 1 through 10 when people come through the doors. If you are given an even-numbered ticket, you are given a prize at the end of the evening. The table shows the results of 500 guests. What is the relative frequency for the guests who will receive a prize? Ticket Number 1 2 3 4 5 6 7 8 9 10 Frequency 48 42 41 56 67 43 39 41 55 68

Relative frequency for guest who will win the prize:

Relative frequency = 50%

Step-by-step explanation:

Total No. of guest = 500

No. of Guests with even-numbered tickets:

Ticket NO. 2 = 42

Ticket NO. 4 = 56

Ticket NO. 6 = 43

Ticket NO. 8 = 41

Ticket NO. 10 = 68

Total No. of Guest with even-numbered ticket = 42+56+43+41+68

Total No. of Guest with even-numbered ticket = 250

So.

Relative frequency = (frequency of desirable event/ total frequency) · 100

Relative frequency = (250/500)· 100

Relative frequency = 50%

Upper left corner

Further Explanation:

The piecewise function is broken down into three parts which I'll refer to as A, B and C (moving down the rows).

Part A is y = -4 but only if x is -3 or smaller. Points on this line include (-3,-4), (-4,-4), (-5,-4), etc. Basically any point where the y value is -4, and the x value is -3 or smaller.

Part B of this piecewise funciton is exactly one point which is (2,0). We plot y = 0 but only when x = 2.

Finally, part C is the horizontal line through y = 3 but we only graph this line if x is larger than 2. Two points on this line are (2,3) and (3,3). The point (2,3) is an open circle because of the fact that x > 2. So x = 2 is not allowed for this piece.

Put this all together, and you get the graph shown in the upper left corner as the final answer.

Note: the bottom left corner is very close to the proper answer, but the presence of an open hole at (-3,-4) is why this is not the actual answer. We are including this point as part of the first piece. This point is included because of the "or equal to" as part of the inequality.