At a highschool students can choose between 3 art electives and 4 history electives and 5 computer electives Each student can choose two electives . What is the approximate probability that a student uses a computer elective and an art elective

The answer to the question is

The approximate probability that a student uses a computer elective and an art elective is 15/144 ≈ 0.104 or 10.4 %

Step-by-step explanation:

The available options are

3 art electives, 4 history electives, 5 computer electives

Therefore the total number of electives = 3+4+5 =12

The probability of choosing a computer elective P(computer) = 5/12

and the probability of choosing an art elective P(art)= 3/12

Therefore the combined probability of selecting an computer and an art elective is 3/12×5/12 = 15/144 =0.104 or 10 %

sin(x) = 6/10. cos(y) = 6/10. The relationship is that sin(x)/cos(y) = 1 and or cos(y)/sin(x) = 1

Step-by-step explanation: First we solve for the hypotenuse using the pythagorean theorem 8^2 + 6^2 = x^2 = 100 then we do sqrt(100) = 10. So the hypotenuse is 10. The value of sin(x) is the opposite/hypotenuse. So this makes it 6/10. The cos(y) is going to be the adjacent/hypotenuse. The adjacent side is 6. So cos(y) is also 6/10. Their relationship is that if you take sin(y)/cos(x) it = 1. 6/10 / 6/10 = 1.