At a large university, 15% of students are left-handed. A psychology professor selects a random sample of 10 students and records L = the number of left-handed students in the sample. Describe the assignment of digits to the outcomes being left-handed and being right-handed:
left-handed = 1–15, right-handed = 16–100
left-handed = 1–5, right-handed = 6–0
left-handed = evens, right-handed = odds
left-handed = 00–14, right-handed = 15–99

Mean Absolute Deviation (MAD) of 11, 0.5: 5.25

Mean Absolute Deviation (MAD) of 9.5, 0.502: 4.499

Mean Absolute Deviation (MAD) of 9.5, 0.5045: 4.49775

Mean Absolute Deviation (MAD) of 7.9, 0.507: 3.6965

Mean Absolute Deviation (MAD) of 4.8, 0.51: 2.145

Step-by-step explanation:

1. Find the mean (average)

2. Find the difference between each data value and the mean

3. Take the absolute value of each difference

4. Find the mean (average) of these differences

Hope this helped buddy :D