Mathematics: At a teddy bear workshop, customers can select from black, brown, gold, white, blue, or pink for their bear s colors. If a father randomly selects two bear colors, what is the probability that he will select a white bear for his son and a pink bear for his daughter? The father cannot pick the same color for both bears.

1 + 4 is 5 2+ 4 = 6 3 + 4 = 7 I hope that s it...

At a teddy bear workshop, customers can select from

stmy1969

11.04.2021

$P(White\ and\ Pink) = \frac{1}{30}$

Step-by-step explanation:

Given

Colors: Black, Brown, Gold, White, Blue, Pink

Required

P(White and Pink)

Since the father can not select the same color, then it is a selection without replacement.

So, we have:

$P(White\ and\ Pink) = [P(White)\ and\ P(Pink)]$

$P(White\ and\ Pink) = [P(White)\ *\ P(Pink)]$

This gives:

$P(White\ and\ Pink) = [\frac{1}{6}\ *\frac{1}{6-1}]$

$P(White\ and\ Pink) = [\frac{1}{6}\ *\frac{1}{5}]$

$P(White\ and\ Pink) = [\frac{1}{30}]$

$P(White\ and\ Pink) = \frac{1}{30}$

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