At the average cost of $.562 per mile, find the

Ответ:

calebcoolbeans6691

09.01.2022

Mathematics

$236.04

Step-by-step explanation :

Since this question asks the cost we will set up a equation like this

.562 x 420

This will get us how much is needed for the trip.

After making the equation, you will multiply it like a normal equation.

Getting your answer, $236.04

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Ответ:

serenityjohnson98765

27.05.2023

Mathematics

Answer is (c) 2 and 4======it's easier to differentiate when we expand it out.this $(t-2)^2$ expands to $t^2 - 4t + 4$ $\begin{aligned} v(t) & = (t-5)(t-2)^2 \\ & = (t-5)(t^2 - 4t + 4) \end{aligned}$ distribute $(t^2 - 4t + 4)$ into $(t-5)$ $\begin{aligned} v(t) & = t(t^2 - 4t + 4) - 5(t^2 - 4t + 4) \\ & = t^3 - 4t^2 + 4t - 5t^2 + 20t - 20 \\ & = t^3 -9t^2 + 24t - 20 \end{aligned}$ differentiate this function to get the acceleration function (since is just velocity, and rate of change of velocity is acceleration) $\begin{aligned} v(t) & = t^3 -9t^2 + 24t - 20 \\ v'(t) & = 3t^2 - 18t + 24 \end{aligned}$ find where the acceleration $v'(t)$ is equal to zero by setting $v'(t)$ to be zero and solving for x. $\begin{aligned} 0 & = 3t^2 - 18t + 24 \\ 0 & = 3(t^2 - 6t + 8) \\ \tfrac{0}{3} & = \tfrac{3(t^2 - 6t + 8)}{3} \\ 0 & = t^2 - 6t + 8 \end{aligned}$ two integers that multiply to get 8 and add to get -6 are -4 and -2 $0 = (t-4)(t-2)$ by the zero product property, either one of these factors can be equal to zero to make the overall product 0 (0 times anything is 0).solutions are t = 4 and t = 2. therefore, choice c.

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At the average cost of $.562 per mile, find the cost to travel 420 miles.

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