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kristieroth1
05.09.2020 •
Mathematics
At the beginning of spring, Taylor planted a small sunflower in her backyard. When it
was first planted, the sunflower was 25 inches tall. The sunflower then began to grow
at a rate of 2 inches per week. How tall would the sunflower be after 7 weeks? How
tall would the sunflower be after w weeks?
Solved
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Ответ:
Step-by-step explanation:
a) Given the proportion:
\frac{2}{15}=\frac{3}{2}x
You must solve for "x":
(\frac{2}{3})(\frac{2}{15})=xx=\frac{4}{45}
b) Given:
\frac{9}{4}=\frac{x+2}{x+3}
Solve for "x":
(x+3)(\frac{9}{4})=x+2frac{9}{4}x+\frac{27}{4}=x+2frac{9}{4}x-x=2-\frac{27}{4}frac{5}{4}x=-\frac{19}{4}x=(-\frac{19}{4})(\frac{4}{5})x=-\frac{19}{5}
c) \frac{x+5}{x}=\frac{10}{8}
Solve for "x":
x+5=\frac{10}{8}x5=\frac{10}{8}x-x5=\frac{1}{4}x(5)(4)=xx=20
d) \frac{3x}{21}=\frac{5}{7}
Solve for "x":
3x=(\frac{5}{7})(21)x=\frac{15}{3}x=5
e) \frac{2x-1}{x+2}=\frac{3}{5}
Solve for "x":
(5)(2x-1)=(3)(x+2)10x-5=6x+610x-3x=6+57x=11x=\frac{11}{7}
f) \frac{x-5}{3}=\frac{x-1}{4}
Solve for "x":
(4)(x-5)=(x-1)(3)4x-20=3x-34x-3x=-3+20x=17