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maronetham6253
23.09.2019 •
Mathematics
At the curb a ramp is 11 inches off the ground. the other end of the ramp rests on the street 55 inches straight out from the curb. write a linear equation in slope-intercept form that relates the height y of the ramp to the distance x from the curb.
y = 5x + 11
y = -1/5x + 11
y = -1/5x + 55
y = 1/5x + 55
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Ответ:
Step-by-step explanation:
The slope intercept form of a line is given by![y=mx+b](/tpl/images/0254/3645/904ac.png)
Here m is the slope and b is the y intercept.
Now, the slope can be defined as the ratio of rise and run.
It has been given that at the curb a ramp is 11 inches off the ground. It means the rise is -11.
Now, other end of the ramp rests on the street 55 inches straight out from the curb. Hence, run is 55.
Therefore, the slope is given by
Therefore, the linear equation is
Also, from the second condition, we have a point (55,0)
Therefore, the linear equation is
Ответ:
=11/55
=1/5
General equation;
y=mx+c
y=1/5x+c
Replacing for x and y;
11=1/5*55+c
c=0
The equation then should be;
y=1/5x
Ответ:
-4/6, -6/9, -8/12
Step-by-step explanation:
All you're doing is multiplying each side, like for -4/6, you multiply -2 by 2 and multiply 3 by 2 to get -4/6. Remember whatever you do to one side you must do to the other