At the end of one day, the value of a share of a certain stock was $12. over the next three days, the change in the value of the share was -$1, then, -$1, and then $3. a. write an expression that describes the situation.b. evaluate the expression.c. what does your answer to part b mean in context of the problem?

Given

end of one day, the value of a share of a certain stock was $12

next three days

the change in the value of the share was -$1, then, -$1, and then $3

ANSWER

proof of (a)

As given  in the question

end of one day, the value of a share of a certain stock = $12

next three days

change in the value of the share was -$1, then, -$1, and then $3

The expression that describes the situation be

= $12 - $1 -$1 + $3

proof of  (b)

The expression that describes the situation be

= $12 - $1 -$1 + $3

solving the above expression

we get

= $13

proof of c

The answer to part b mean in context of the problem is ,

The value of a share of a certain stock  was  $12 at one day end and after the next three days, the change in the value of the share was -$1, t, -$1, $3 than the value of share becomes $13.

Hence proved

The shortest distance from the streetlight to  the flagpole is 13 yards

Step-by-step explanation:

the way to solve this question is by using the Pythagoras Theorem

A^ + B^=C^

12 ^ + 5^=C^

144 + 25=C^

169=C^

C=13

^= squared