Atennis court for singles play is 78 feet long and 27 feet wide. a: the court for doubles play is 9 feet wider than the court for singles play.how much more area is covered by the tennis court used for doubles play? b: the junior court for players 8 and under is 36 feet long and 18 feet wide.how much more area is covered by the tennis court used for singles play? c: the court for players 10 and under is 18 feet shorter than the court for singles play.how much more area is covered by the tennis court used for the singles play?

The tennis court for singles play has an area of 
Area = 78 * 27 
Area = 2106 ft^2

The tennis court for doubles play has an area of 
Area = 78 * (27 + 9)
Area = 78 * 36
Area = 2808 ft^2

= 2808 - 2106
= 702 ft^2

(A) So, the doubles play court covered 702 ft^2 more area.

The tennis court for players 8 - under has an area of 
Area = 36 * 18
Area = 648 ft^2

= 2106 - 648
= 702 ft^2

(B) So, the single play court covered 1458 ft^2 more area.

The tennis court for 10 players has an area of 
Area = (78 - 18) * 27
Area = 60 * 27
Area = 1620 ft^2

= 2106 - 1620
= 486 ft^2

(C) So, the singles play court covered 486 ft^2 more area.

I think A is the answer
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