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neariah24
18.10.2019 •
Mathematics
Atour bus normally leaves for its destination at 5: 00p.m. for a 378 mile trip. this week however, the bus
leaves at 6: 00 p.m. to arrive on time, the driver drives 9 miles per hour faster than normal what is the normal
speed of the bus?
Solved
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Ответ:
54 mph
Step-by-step explanation:
we know D = RT, where
D is distance
R is rate/speed
T is time
Normally:
D = RT
378 = RT
This week:
D = RT
378 = (R+9)(T-1)
These are the 2 equations we can write:
Let's mutliply out the last equation:
378 = (R+9)(T-1)
378 = RT - R + 9T - 9
387 = RT - R + 9T
we know RT = 378 and T = 378/R, we replace:
387 = 378 - R + 9(378/R)
9 = -R + 3402/R
Now solving:
R can't be negative, so we take R = 54 miles per hour
Ответ:
I didn,t get it
Step-by-step explanation: