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veronica25681
06.07.2019 •
Mathematics
Atoy company has determined that the revenue generated by a particular toy is modeled by the following equation: 10x - 0.025x² the variable x is measured in thousands of toys produced, and r(x) is measured in thousands of dollars. what is the maximum revenue the company can earn with this toy?
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Ответ:
Maximum revenue = 1000 thousands of dollars.
Explanation:
We have the revenue equation
, where x is measured in thousands of toys produced, and r(x) is measured in thousands of dollars.
At maximum revenue the derivative of equation is zero
So,![r'(x)=0\\ \\10 - 0.025*2x=0\\ \\ x=10/0.05\\ \\ x=1000/5=200](/tpl/images/0058/9491/6533c.png)
So maximum revenue is when 200 thousands of toys are produced.
Maximum revenue,![r(200)=10*200 - 0.025*200^2\\ \\ r(200)=1000](/tpl/images/0058/9491/abbd2.png)
Maximum revenue = 1000 thousands of dollars.
Ответ:
Step-by-step explanation:
2 3/4 = 11/4 (there are 4/4 in 1, so 2 have 8/4, and then plus 3/4 = 11/4).
1 4/7 = 11/7 (7/7 in 1 plus 4/7 = 11/7)
so, we actuality have
11/4 ÷ 11/7 = 11/4 × 7/11 = (7×11)/(4×11) = 7/4 = 1 3/4