Aturntable rotates counterclockwise at 78 rpm. a speck of dust on the turntable is at an initial angular position of 0.45 radians at t = 0 seconds. what is the angular position of the speck at t = 8.8 seconds relative to a reference angular position of 0 radians (your answer should be between 0 and 2\piπ radians, round answer to one decimal)?

Displacement will be 11 revolution and 1.02π radian

Step-by-step explanation:

We have given that initial angular position = 0.45 radian

Angular speed

Time is given as t = 8.8 sec

So angular displacement in 8.8 sec

As he has already covered 0.45 radian

So total angular displacement = 0.45 + 71.8432 = 72.2932 radian

We know that 1 revolution = 2π = 2×3.14 = 6.28 radian

So 11 revolution = 11×6.28 = 69.08 radian

Left dispalcement = 72.2932 - 69.08 = 3.2132 radian = 1.02π radian

A = s2

Step-by-step explanation:

Extra info : Area of a square = side times side. Since each side of a square is the same, it can simply be the length of one side squared. If a square has one side of 4 inches, the area would be 4 inches times 4 inches, or 16 square inches.

Hope I helped! :)