Mathematics: Awheel initially has an angular velocity of 18 rad/s, but it is slowing at a constant rate of 2 rad/s 2 . by the time it stops, it will have turned through approximately how many revolutions?

Awheel initially has an angular velocity of 18

jholland03

13.03.2022

13 revolution

Step-by-step explanation:

Given data

Wheel initial angular velocity $\left ( \omega \right )$ =18 rad/s

Contant angular deaaceleration $\left ( \alpha \right )$ =2 rad/s^2

Time required to stop wheel completely=t sec

$\omega =\omega_0 + \aplha t$

0 =18 + $\left ( -2\right )t$

t=9 sec

Therefore angle turn in 9 sec

$\theta$ = $\omega_{0} t$ + $\frac{1}{2}$ $\left ( \alpha\right )t^{2}$

$\theta$ = $18\times 9$ + $\frac{1}{2}$ $\left ( -2\right )\left ( 9\right )^2$

$\theta$ =81rad

therefore no of turns(n) = $\frac{81}{2\times \pi}$

n=12.889 $\approx$ 13 revolution

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person4936

25.08.2022

The two figures are congruent.

Step-by-step explanation:

They are reflected so they are congruent

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