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patrick171888
15.08.2019 •
Mathematics
Awoman is 3 times as old as her son.8 years ago the product of their ages was 112. find their present ages
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Ответ:
Son 12 and woman 36 years old.
Step-by-step explanation:
Let the age of the woman now be 3x years, then her son's age = x years.
8 years ago the woman's age was (3x-8) and her son's age was (x- 8) years, so:
(3x - 8)(x - 8) = 112
3x^2 - 32x + 64 = 112
3x^2 - 32x - 48 = 0
3x^2 - 36x + 4x - 48 = 0
3x(x - 12) + 4(x - 12) = 0
(3x + 4)(x - 12 ) = 0
x = -1.33... , 12 . ( We ignore the negative value).
So the son's age is 12 and the woman's age is 36.
Ответ:
mean, 15, less, median, april, much
Step-by-step explanation: