sm908361
13.11.2020 •
Mathematics
B. Solve the problem:
Mrs. Reyna is planning to fence her vacant lot for a parking space. The desired length of the lot is 6 m longer than its width. What will be the possible dimensions of the rectangular parking space if it should be less than 40m2?
(Hint: length x width = Area of rectangle)
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Ответ:
Step-by-step explanation:
Given
Area of the rectangle =Length × width
Given
The desired length of the lot is 6 m longer than its width, then L = 6+W
A = LW
40 = (6+W)W
40= 6W+W²
W²+6W -40 = 0
W²+10W-4W-40 = 0
W(w+10)-4(w+10) = 0
W+10 = 0 and w-4 = 4
W = -10 and w = 4
Width can't be negative
W = 4m
Since L = 6+w
L = 6+4
L = 10m
Hence the possible dimension s 4m by 10m
Ответ:
I think the area is 72 sorry if it is wrong I tried
Step-by-step explanation: