\begin{aligned} &f(t)=\dfrac{2t+7}{t-3} &h(n)=-2n^2-3n+1

Ответ:

itzhari101

01.10.2020

f(h(-1))=-11

Step-by-step explanation:

Given:

$\begin{aligned} &f(t)=\dfrac{2t+7}{t-3} \\\\ &h(n)=-2n^2-3n+1 \end{aligned}$

We want to determine the value of f(h(-1))

First, we evaluate h(-1)

$h(-1)=-2(-1)^2-3(-1)+1 =-2+3+1\\h(-1)=2$

Therefore: f(h(-1))=f(2)

$f(2)=\dfrac{2(2)+7}{2-3}\\=\dfrac{4+7}{-1}\\=-11$

Therefore: f(h(-1))=-11

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Cutegirlrocks1071

19.04.2020

need to see the image fam other wise I can't help ya

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