![jackchris2732](/avatars/5457.jpg)
jackchris2732
24.03.2020 •
Mathematics
Below, n is the sample size, p is the population proportion and p is the sample proportion. Use the Central Limit Theorem and the TI-84 calculator to find the probability. Round the answer to at least four decimal places.
n= 200
p=0.10
Solved
Show answers
More tips
- C Computers and Internet What Are Peers and Seeds in Torrenting?...
- H Health and Medicine 10 Simple Techniques on How to Boost Your Mood...
- G Goods and services How to Choose the Right High Chair for Your Baby?...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
- S Style and Beauty How to braid friendship bracelets?...
Answers on questions: Mathematics
- M Mathematics Let f stand for the number of footprints Jayden finds.Which bar model represents he problem...
- M Mathematics Look in picture below:...
- M Mathematics (x−2)^2 combind like turns...
- M Mathematics What is the equation of the line...
- M Mathematics (6x + 4)2 = 8 Is it true or false...
- M Mathematics (x - 10) + (3x – 6) please hel...
- M Mathematics A carnival game asks players to choose a door and then choose a curtain behind the door. There are 3 doors and 4 curtains behind each door. How many possible choices...
- M Mathematics Which would be the most appropriate subject line for the e-mail with this claim? Claim: Cell phones should be allowed in schools because banning them is no longer...
- M Mathematics . Nine students in a college math class took a pre-test. We are interested in whether the pre-test is useful for predicting final course percentage. Here are the...
- M Mathematics True or False, the median is always in between the first and third quartile? *...
Ответ:
Step-by-step explanation:
Hello!
Be it a variable with a binomial distribution, if n≥30, n*p≥5 and n*q≥5, then you can approximate the distribution of the sampling proportion to normal:
^p≈N(p;(p*q)/n)
Where p is the probability of success and q is the probability of failure (q= 1-p)
Under this distribution you can calculate the probabilities using the standard normal approximation:
Find P(0.06 < p-hat < 0.16)=_______
To find the probability inside the given interval you have to subtract the accumulated up to the lower bond to whats accumulated up to the upper bound of the interval:
P(^p<0.16)-P(^p<0.06)
Now you standardize both terms to obtain Z-values and look for the corresponding probabilities in the Z-table:
P(Z<(0.16-0.10)/(√(0.10*0.9)/200))-P(Z<(0.06-0.10)/(√(0.10*0.9)/200))
P(Z<2.82)-P(Z<-1.89)
Now what's left is to look for the values in the Z-table. All negative values are in the left entry and all positive values are in the right entry. The integer and first decimal can be found in the first column of the table, the second decimal can be found in the first row of the table when you cross both, you find the corresponding cumulative probability.
P(Z<2.82)-P(Z<-1.89)= 0.99760-0.02938= 0.96822
I hope this helps!
Ответ: