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xxsyd21
21.02.2020 •
Mathematics
Bridge is a game played by 4 players with a standard 52 playing card deck of cards. Each
player is dealt 13 cards from the deck and order doesn't matter.
(b) How many different bridge hands are possible if they are required to have all four
aces?
(c) How many different bridge hands are possible if at least one card is an ace?
(d) How many bridge "games" are possible, namely, in how many ways can the 52
cards be distributed to four players?
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Ответ:
Part b: The number of ways in which there will be four aces is 1677106641
Part c: The number of ways in which there will be at least one ace is 442085310304
Part d: The number of ways in which cards can be dealt is 635013559600
Step-by-step explanation:
Part b
The number of different bridge hands with four aces is
As Total Number of Hands with 4 aces is given as
As the order does not matter, thus the number of Hands with 4 aces is given as
So the number of ways in which there will be four aces is 1677106641
Part c
Total cards without ace = 48
Number of hands of (no ace) =![n_{no aces}=48C13=192928249296](/tpl/images/0518/6886/cc935.png)
Number of hands of (at least one ace)
So the number of ways in which there will be at least one ace is 442085310304
Part d
As Total Number of Hands is given as
Total Cards=52
Cards per Player=13
As the order does not matter, thus the number of Hands is given as
So the number of ways in which cards can be dealt is 635013559600
Ответ:
19
Step-by-step explanation:
Here df denote the degree of freedom
The degree of freedom are the value which are free to vary
The degree of freedom can be calculated by subtracting one from the total sample space
Here total sample space that is n is given as 19
So degree of freedom that df =20-1 =19
So for the given question the degree of freedom will be 19