By applying the rules of probability to the following cross, rr x rr, determine the probability of the offspring being homozygous recessive?
a. 1/2
b. 1/4
c. 3/4

Using the Punnette Square :
R r 
R RR Rr 
r Rr rr 
Hence,
By applying the rules of probability  Rr x Rr, the probability of the offspring being homozygous recessive will be one fourth or a quarter.
SO the best is :

B. 1/4

18x+36

Step-by-step explanation:

1. Simplify  \frac{4}{5}(30x-40)54(30x−40)  to  \frac{4(30x-40)}{5}54(30x−40).

-\frac{4(30x-40)}{5}+42x+4−54(30x−40)+42x+4

2. Factor out the common term 1010.

-\frac{4\times 10(3x-4)}{5}+42x+4−54×10(3x−4)+42x+4

3. Simplify  4\times 10(3x-4)4×10(3x−4)  to  40(3x-4)40(3x−4).

-\frac{40(3x-4)}{5}+42x+4−540(3x−4)+42x+4

4. Simplify  \frac{40(3x-4)}{5}540(3x−4)  to  8(3x-4)8(3x−4).

-8(3x-4)+42x+4−8(3x−4)+42x+4

5. Expand by distributing terms.

-(24x-32)+42x+4−(24x−32)+42x+4

6. Remove parentheses.

-24x+32+42x+4−24x+32+42x+4

7. Collect like terms.

(-24x+42x)+(32+4)(−24x+42x)+(32+4)

8. Simplify.

18x+3618x+36

hope this helps