cam961

21.11.2019 • 

Mathematics

By determining f prime left parenthesis x right parenthesis equals modifyingbelow lim with h right arrow 0 startfraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right parenthesis over h endfractionf′(x)=limh→0 f(x+h)−f(x) h, find f prime left parenthesis 7 right parenthesisf′(7) for the given function. f left parenthesis x right parenthesis equals 5 x squaredf(x)=5x2 f prime left parenthesis 7 right parenthesisf′(7)equals=nothing (simplify your answer.)

Ответ:

leleee10

26.08.2022

Mathematics

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4 I'm so glad to help! :) :P

Step-by-step explanation:

first u put two fingers up then another two. u count it. and there u go the awnsers it four. or u can count. 1 2 3 4

1 2 1 2

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