Mathematics: C = 7a^4+ + 5a²b2 – 3b^4 D=5a^4 + 7a²b^2 + 3b^4 C - D =

Honestly I don’t get the question...

C = 7a^4+ + 5a²b2 – 3b^4 D=5a^4 + 7a²b^2 + 3b^4 - id74523454723410415313, brendacauani12345

PearlJam5492

17.03.2022

C-D is: $\mathbf{4b^4 -2a^b^2 -6b^4}$

Step-by-step explanation:

We are given:

$C = 7a^4+ + 5a^2b2 - 3b^4\\D=5a^4 + 7a^2b^2 + 3b^4$

We need to find C-D.

Finding C-D we actually have to subtract D from C

So, finding C-D

$C-D\\= 7a^4+ + 5a^2b2 - 3b^4-(5a^4 + 7a^2b^2 + 3b^4)\\=7a^4+ + 5a^2b2 - 3b^4-5a^4-7a^2b^2-3b^4$

Now, combining the like terms.

Like terms are those that have same variables and exponents.

In our case, $7a^4\: and\: 3b^4, 5a^2b^2\: and\: -7a^b^2, -3b^4\:and\:-3b^4$

$=7a^4 - 3b^4+5a^2b^2 -7a^b^2 -3b^4-3b^4\\=4b^4 -2a^b^2 -6b^4$

So, we get C-D is: $\mathbf{4b^4 -2a^b^2 -6b^4}$

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