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21brooklynmartin
22.07.2021 •
Mathematics
Câu 1: cho hình chóp S.ABC có đáy là tam giác đều cạnh bằng a, cạnh bên SB vuông góc với mặt phẳng (ABC) , SB =2a. Tính thể tích khối chóp S.ABC Câu 2: Cho hình chóp S.ABC với SA, SB,SC đôi một vuông góc và SA=SB=SC +a . TÍnh thể tích của khối chóp S.ABC.
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Ответ:
Step-by-step explanation:
Câu 1: V = 1/3.2a.![\frac{\sqrt{3}}{4}](/tpl/images/1398/0305/8cc4c.png)
= ![\frac{\sqrt{3}}{6} a^{3}](/tpl/images/1398/0305/2a9da.png)
câu 2: Theo đề bài ta có SA là chiều cao và tam giác đáy SBC vuông tại S (hình chóp S.ABC đổi thành chóp A.SBC)
=> V = 1/3 SA.(diện tích tam giác SBC) = 1/3a.
= ![\frac{a^{3} }{6}](/tpl/images/1398/0305/83d66.png)
Ответ:
Ex: 1÷12, 2÷12, and so on.