Mathematics: Can anyone solve this

Can anyone solve this - id11344707, saintsfan2004

Ответ:

yasminlockser6

23.03.2021

Step-by-step explanation:

${(1 + \cos( \alpha ) + \sin( \alpha ) )}^{2} = \\ 1 + \sin( \alpha ) + \cos( \alpha ) + \sin( \alpha )+ \\ { \sin( \alpha ) }^{2} + \sin( \alpha ) \cos( \alpha ) + \cos( \alpha ) \\ + \sin( \alpha ) \cos( \alpha ) + { \cos( \alpha ) }^{2}$

$= 1 + 2 \sin( \alpha ) + 2 \cos( \alpha ) + { \sin( \alpha ) }^{2} \\ + { \cos( \alpha ) }^{2} + 2 \sin( \alpha ) \cos( \alpha )$

$2(1 + \sin( \alpha ) (1 + \cos( \alpha ) ) = \\ 2(1 + \cos( \alpha ) + \sin( \alpha ) \\ + \sin( \alpha ) \cos( \alpha ) ) = \\ 2 + 2 \cos( \alpha ) + 2 \sin( \alpha ) \\ + 2 \sin( \alpha ) \cos( \alpha )$

$comparing \\ 1 + 2 \sin( \alpha ) + 2 \cos( \alpha ) + { \sin( \alpha ) }^{2} \\ + { \cos( \alpha ) }^{2} + 2 \sin( \alpha ) \cos( \alpha ) \\ = \\ 2 + 2 \cos( \alpha ) + 2 \sin( \alpha ) \\ + 2 \sin( \alpha ) \cos( \alpha ) \\$

$1 + { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} = 2 \\ we \: know \: that \: \\ { \cos( \alpha ) }^{2} + { \sin( \alpha ) }^{2} = 1 \\ so \\ 1 + 1 = 2 \\ 2 = 2 \\ they \: are \: equal$

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Ответ:

JKINGblackstar3502

21.09.2021

Mathematics

70 m^2.

Step-by-step explanation:

Area of the triangle = 1/2 * base * height.

Counting the squares on the coordinate plane:

Base = 7, height = 5

Each square = 2 meters

So the area = 1/2 * 14 * 10

= 70m

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