CAN SOMEBODY HELP SOLVE THE EQUATION

4 m = width of the rectangle.

6 m = length of the rectangle

20 m = perimeter of rectangle

3 m = side of the square

Step-by-step explanation:

Let s = length of side of square

s + 1 = width of rectangle

s + 3 = length of rectangle

Area of rectangle = (s + 1)(s + 3)

Area of square =

So,  (s + 1)(s + 3) + = 33

+ 4s + 3 + = 33

2 + 4s - 30 = 0

2( + 2s - 15) = 0

2(s + 5)(s - 3) = 0

s = -5   or   s = 3

Length of a side cannot be negative, so -5 is ignored

3 m = side of the square

4 m = width of the rectangle

6 m = length of the rectangle

2(4) + 2(6) = 8 + 12 = 20 m = perimeter of rectangle