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kymberlyasher
07.04.2021 •
Mathematics
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Ответ:
ANSWER D
f(-4)=-4(-4)^3-28*(-4)²-32*(-4)+64=0
f(1)=-4-28-32+64=0
f'(x)=-12x²-56x-32
f'(x)=0==>6x²+28x+16=0 ==>x=-2/3 or x=-4
Thus
The graph touches the x axis at x = –4 and crosses the x axis at x = 1.