Mathematics: Can someone help with this please

Can someone help with this please - id7426338, thruhdyjgrt

Ответ:

jech3947

01.02.2022

Mathematics

GH = 9

Step-by-step explanation:

Note:

GI = GH + HI

Plug in the corresponding terms to the corresponding variables:

3x + 8 = (x + 6) + (x + 5)

First, simplify. Combine like terms:

3x + 8 = (2x) + (11)

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 2x and 8 from both sides:

3x (-2x) + 8 (-8) = 2x (-2x) + 11 (-8)

3x - 2x = 11 - 8

x = 3

Plug in 3 for x in the length of GH.

GH = x + 6

GH = 3 + 6

GH = 9

9 is the numerical length of GH.

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Ответ:

potatogirl9300

01.02.2022

Mathematics

Step-by-step explanation:

h(t) = (t + 3)² + 5

A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0

average rate of change in h over the change in t is given as:

$\frac{h(0)-h(-2)}{0-(-2)}=\frac{(0+3)^2+5-[(-2+3)^2+5]}{0+2}=\frac{14-6}{2} =4$

It does not have a negative average rate of change

B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3

average rate of change in h over the change in t is given as:

$\frac{h(-3)-h(-4)}{-3-(-4)}=\frac{(-3+3)^2+5-[(-4+3)^2+5]}{-3+4}=\frac{5-6}{1} =-1$

It have a negative average rate of change

c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(-3)}{4-(-3)}=\frac{(4+3)^2+5-[(-3+3)^2+5]}{4+3}=\frac{54-5}{7} =7$

It does not have a negative average rate of change

D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(1)}{4-(1)}=\frac{(4+3)^2+5-[(1+3)^2+5]}{4-1}=\frac{54-21}{3} =11$

It does not have a negative average rate of change

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