Mathematics: Can someone me with this question?

1. (1st part corresponedes to A)2. (2nd part correspondes to B)3. (3rd part corresponds to D)4. (4th part correspondes to C)....

Can someone me with this question? - id999097, lelseymota123

Ответ:

Manuelperez1373

13.03.2022

Mathematics

So, she can type 50 words in 1 minute, well, 1 minute is 60 seconds, so she really can type 50 words in 60 seconds, hmmmm how many seconds does it take her for 1 word?

$\bf \begin{array}{ccll}
words&seconds\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
50&60\\
1&s
\end{array}\implies \cfrac{50}{1}=\cfrac{60}{s}\implies s=\cfrac{1\cdot 60}{50}\implies s=\cfrac{6}{5}$

so, we know that 1 Jiffy is 1/100 of a second, so, how many Jiffies are there in 6/5 of a second then?

$\bf \begin{array}{ccll}
jiffies&seconds\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&\frac{1}{100}\\\\
j&\frac{6}{5}
\end{array}\implies \cfrac{1}{j}=\cfrac{\quad \frac{1}{100}\quad }{\frac{6}{5}}\implies \cfrac{1}{j}=\cfrac{1}{100}\cdot \cfrac{5}{6}
\\\\\\
\cfrac{1}{j}=\cfrac{5}{600}\implies \cfrac{1\cdot 600}{5}=j\implies 120=j$

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Ответ:

taryn1932

04.06.2021

Mathematics

1.
$(x+5)+ \dfrac{-2}{x-1} = \dfrac{(x+5)(x-1)-2}{x-1} = \dfrac{x^2-x+5x-5-2}{x-1} = \frac{x^2+4x-7}{x-1}$ (1st part corresponedes to A)

2.
$(x-1)+ \dfrac{6}{x-1} = \dfrac{(x-1)(x-1)+6}{x-1} = \dfrac{x^2-2x+1+6}{x-1} = \dfrac{x^2-2x+7}{x-1}$ (2nd part correspondes to B)

3.
$(2x+1)+ \dfrac{-6}{x-1} = \dfrac{(2x+1)(x-1)-6}{x-1}= \\ \dfrac{2x^2-2x+x-1-6}{x-1} = \frac{2x^2-x-7}{x-1}$ (3rd part corresponds to D)

4.
$(2x-1)+\dfrac{6}{x-1}= \dfrac{(2x-1)(x-1)+6}{x-1} = \\ \dfrac{2x^2-2x-x+1+6}{x-1} = \frac{2x^2-3x+7}{x-1}$ (4th part correspondes to C).

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