Can someone please help me with this? It’s due in an hour.. :/

1. Length BC is 1200 ft

2. Angle B is 48.6°

3. Angle C is 41.8°

Step-by-step explanation:

1. Determination of the length BC

Side opposite C = c = 800 ft

Side opposite B = b = 900 ft

Angle A = 89.6°

Side opposite BC = a =?

Using cosine rule, we can obtain length BC as follow:

a² = b² + c² – 2bc CosA

a² = 900² + 800² – 2 × 900 × 800 × Cos89.6

a² = 810000 + 640000 – 1440000 × 0.007

a² = 1450000 – 10080

a² = 1439920

Take the square root of both side

a = √1439920

a ≈ 1200 ft

Thus, length BC is 1200 ft

2. Determination of angle B

Side opposite B = b = 900 ft

Side opposite A = a = 1200 ft

Angle A = 89.6°

Angle B =?

Angle B can be obtained by using sine rule as follow:

a / Sine A = b / Sine B

1200 / Sine 89.6° = 900 / Sine B

Cross multiply

1200 × Sine B = 900 × Sine 89.6°

1200 × Sine B = 900

Divide both side by 1200

Sine B = 900/1200

Sine B = 0.75

Take the inverse of Sine

B = Sine¯¹ 0.75

B = 48.6°

Thus, angle B is 48.6°

3. Determination of angle C

Side opposite C = c = 800 ft

Side opposite A = a = 1200 ft

Angle A = 89.6°

Angle C =?

Angle C can be obtained by using sine rule as follow:

a / Sine A = c / Sine C

1200 / Sine 89.6° = 800 / Sine B

Cross multiply

1200 × Sine C = 800 × Sine 89.6°

1200 × Sine C = 800

Divide both side by 1200

Sine C = 800/1200

Sine C = 0.6667

Take the inverse of Sine

C = Sine¯¹ 0.6667

C = 48.6°

Thus, angle C is 41.8°