Mathematics: Can someone solve this?

PiStep-by-step explanation:sin(e) = - 1, e=arcsin(-1)=pi...

Can someone solve this? - id6268109, AbhiramAkella

Ответ:

gladyscasper44

25.01.2022

Mathematics

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

$\cos \left(91^{\circ \:}\right)=-0.01745\dots$

$c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi$

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Ответ:

Bvrz6198

05.08.2021

Mathematics

Step-by-step explanation:

sin(e) = - 1, e=arcsin(-1)=pi

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Can someone solve this?

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