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lachereyon11

30.07.2020

Mathematics

Step-by-step explanation:

14.

by pythagoras,s theorem

$x=\sqrt{2^2+2^2} =\sqrt{8} =\sqrt{4 \times 2} =2\sqrt{2} \\y^2=x^2+2^2=(2\sqrt{2} )^2+2^2=8+4=12=4 \times 3\\y=2\sqrt{3}$

15.

first perpendicular=y(say)

and second perpendicular=z (say)

y²=9²+7²=81+49=130

z²=y²+5²=130+25=155

x²=z²+4²=155+16=171

x=√(171)

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