Can you stop checking for factor pairs when you find a pair that repeats? explain

Solution:

Consider numbers which are Squares,cubes, fourths, fifths of some natural numbers.

For example, Starting from squares of some natural number: 4,9,16,25,36,49,64

and their factors , which are 4= 1 × 2×1×2

9=1×3×1×3

16=2×1×2×1×2×1×2×1

25=1×5×1×5

36=2×3×2×3

64=2×4×2×4

Now coming to cubic numbers

8= 1 ×2×1×2×1×2

27= 1×3×1×3×1×3

3125= 3 ×5×3×5×3×5

So,the numbers whose factor pairs repeats are square, cubic, fourth,Fifth ,Sixth andhigher powers of natural Numbers.

→→→So, we just need to check that whether those numbers whose factor pairs repeats are Squares, cubes or higher powers of natural numbers.

Step-by-step explanation:

Hello there!

Algebra 1

The first thing we should find is the missing angle

Because this is a right triangle we can solve it using the Pythagorean Theorem

The Pythagorean theorem states that the sum of the two legs squared equal the hypotenuse squared

the formula... where a and b = legs and c = hypotenuse

we are given two legs so we plug in a and b and solve for c

so we can conclude that the missing side length ( or z) equals 25

now to solve for the angles

Trigonometry

We can solve for y using sin

sin = opposite side divided by the hypotenuse

the opposite of y is 7 and the hypotenuse is 25

so we set up an equation

now we solve for y

then we round to the nearest hundredth

so we can conclude that angle labeled y = 16.26

basic geometry

Remember all of the angles in a triangle add up to equal 180 so we can find x by subtract the known angles from 180

180 - 90 - 16.26 = 73.74 so we can conclude that x = 73.74