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rigobertogarza2
16.02.2020 •
Mathematics
CH is an altitude of the triangle ABC, m∠A = 60°, m∠B = 45°. Circle with the diameter CH intersects sides AC and BC at points N and M respectively. Find the area (exact value) of the quadrilateral CMHN if AN = 1.
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Ответ:
(6+3√3)/2
Step-by-step explanation:
ΔANH is a 30°-60°-90° right triangle. The side lengths of such a triangle are in the ratio 1 : √3 : 2. This means side NH has length √3, and segment NC has length 3. The altitude CH is then 2√3, so the radius of the circle is √3.
The area of triangle CHN is ...
(1/2)(√3)(3) = (3/2)√3
The area of triangle CHM is ...
(1/2)(2√3)(√3) = 3
Then the area of quadrilateral CMHN is ...
3 + (3/2)√3 = (6+3√3)/2
Ответ:
"A valid inference is one that is true about the Data based on a representative example. "
The answers to the question are bold for you. I hope this helps answer your question! And have a good day!